# Thread: VCE Maths questions help

1. ## Re: VCE Maths questions help

f(x) = (x-3)^2 (x+2)
find x: f(x) >6
what does the question mean?  Reply With Quote

2. ## Re: VCE Maths questions help Originally Posted by boredsatan f(x) = (x-3)^2 (x+2)
find x: f(x) >6
what does the question mean?
Find all values of x such that f(x) > 6.  Reply With Quote

3. ## Re: VCE Maths questions help

(x-3)^2(x+2) >6
so, (x-3)^2(x+2) =6
so, (x-3)^2(x+2) - 6 = 0
is this correct so far?  Reply With Quote

4. ## Re: VCE Maths questions help Originally Posted by boredsatan (x-3)^2(x+2) >6
so, (x-3)^2(x+2) =6
so, (x-3)^2(x+2) - 6 = 0
is this correct so far?
anyone?  Reply With Quote

5. ## Re: VCE Maths questions help Originally Posted by boredsatan (x-3)^2(x+2) >6
so, (x-3)^2(x+2) >6
so, (x-3)^2(x+2) - 6 > 0
is this correct so far?
yeah it's correct but keep the inequality signs, i have fixed it above

once you solve that inequality you will see that the roots are +sqrt(3), -sqrt(3) and 4

and if u draw the graph the inequality satisfies when -sqrt(3) < x < +sqrt(3) and x > 4  Reply With Quote

6. ## Re: VCE Maths questions help

Consider the curve with equation y = 2x^2 - x
a. express the gradient of the secant through the points on the curve where x = -1 and x = -1+ h in terms of h
b. Use h = 0.01 to obtain an estimate of the gradient of the tangent to the curve at x = -1
c. deduce the gradient of the tangent to the curve at the point where x = -1
no idea how to do part b and c  Reply With Quote

7. ## Re: VCE Maths questions help Originally Posted by boredsatan Consider the curve with equation y = 2x^2 - x
a. express the gradient of the secant through the points on the curve where x = -1 and x = -1+ h in terms of h
b. Use h = 0.01 to obtain an estimate of the gradient of the tangent to the curve at x = -1
c. deduce the gradient of the tangent to the curve at the point where x = -1
no idea how to do part b and c
Once you've done a), b) is easy (just put h = 0.01 in your formula from a)). To get the answer to c), take the limit as h -> 0 in your answer for part a).  Reply With Quote

8. ## Re: VCE Maths questions help

(1√6 - 2√9+3√4)/(9√4-4√9)
How would this be simplified?  Reply With Quote

9. ## Re: VCE Maths questions help Originally Posted by boredsatan (1√6 - 2√9+3√4)/(9√4-4√9)
How would this be simplified?
Anyone?  Reply With Quote

10. ## Re: VCE Maths questions help Originally Posted by boredsatan (1√6 - 2√9+3√4)/(9√4-4√9)
How would this be simplified?
sqrt(9) = 3,
sqrt(4) = 2.
The fraction will simplify to (sqrt(6))/(6).  Reply With Quote

11. ## Re: VCE Maths questions help

is 3/(x-1)+2 a polynomial ? If no, why isn't it a polynomial?  Reply With Quote

12. ## Re: VCE Maths questions help Originally Posted by boredsatan is 3/(x-1)+2 a polynomial ? If no, why isn't it a polynomial?
no

polynomials have integer powers  Reply With Quote

13. ## Re: VCE Maths questions help Originally Posted by Squar3root no

polynomials have integer powers
what are integer powers?  Reply With Quote

14. ## Re: VCE Maths questions help

thanks
for the help  Reply With Quote

15. ## Re: VCE Maths questions help Originally Posted by boredsatan what are integer powers?
Powers that are integers (whole numbers)

Also polynomials must have POSITIVE integer powers not just integers, so y = x^-3 isn't a polynomial  Reply With Quote

16. ## Re: VCE Maths questions help Originally Posted by boredsatan what are integer powers?  Reply With Quote

17. ## Re: VCE Maths questions help Originally Posted by boredsatan is 3/(x-1)+2 a polynomial ? If no, why isn't it a polynomial? Originally Posted by Squar3root no

polynomials have integer powers Originally Posted by boredsatan what are integer powers? Originally Posted by pikachu975 Powers that are integers (whole numbers)

Also polynomials must have POSITIVE integer powers not just integers, so y = x^-3 isn't a polynomial Originally Posted by 1729 my bad

yes this

polynominals have integer powers > 0

1729 mentioned toe subset above  Reply With Quote

18. ## Re: VCE Maths questions help

How would you show that the points (5,2). (-2,1) and (1,5) form the vertices of an isosceles triangle?  Reply With Quote

19. ## Re: VCE Maths questions help

all of the points (-1,-6), (0,-6), (1,-2) and (2,2) lie on the cubic with equation ax^3 + bx^2 + cx + d.
Find the value of d
determine 3 simultaneous equations that will enable solutions to a, b, and c to be found
find the values of a, b, and c, and determine the equation of the cubic  Reply With Quote

20. ## Re: VCE Maths questions help

a graph has the rule
y = a/(x-b)^2 + c
the y intercept is located ta (0,-1) and an asymptote exists at y = 2, determine the values of a, b, and c  Reply With Quote

21. ## Re: VCE Maths questions help

Would appreciate any help. Have a maths exam in 4 days  Reply With Quote

22. ## Re: VCE Maths questions help

If f(x) = 3x and g(x) = x+2, then what is the value of g(f(-1))  Reply With Quote

23. ## Re: VCE Maths questions help Originally Posted by boredsatan all of the points (-1,-6), (0,-6), (1,-2) and (2,2) lie on the cubic with equation ax^3 + bx^2 + cx + d.
Find the value of d
determine 3 simultaneous equations that will enable solutions to a, b, and c to be found
find the values of a, b, and c, and determine the equation of the cubic  Reply With Quote

24. ## Re: VCE Maths questions help Originally Posted by boredsatan If f(x) = 3x and g(x) = x+2, then what is the value of g(f(-1))
First find f(-1).

Then plug this into the equation for g(x) to get the value of g(f(-1)).  Reply With Quote

25. ## Re: VCE Maths questions help Originally Posted by boredsatan If f(x) = 3x and g(x) = x+2, then what is the value of g(f(-1))  Reply With Quote

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