f(x) = (x-3)^2 (x+2)
find x: f(x) >6
what does the question mean?
y = (x-2)^2 + 1
inverse function
x = (y-2)^2 + 1
(y-2)^2 + 1 = x
(y-2)^2 = x - 1
y - 2 = √(x-1)
y = √(x-1) + 2
is this correct?
year 11 2017
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f(x) = (x-3)^2 (x+2)
find x: f(x) >6
what does the question mean?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
(x-3)^2(x+2) >6
so, (x-3)^2(x+2) =6
so, (x-3)^2(x+2) - 6 = 0
is this correct so far?
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ATAR: 36.85 | TAFE Diploma of Technical Engineering @ Mt Druitt Campus
Consider the curve with equation y = 2x^2 - x
a. express the gradient of the secant through the points on the curve where x = -1 and x = -1+ h in terms of h
b. Use h = 0.01 to obtain an estimate of the gradient of the tangent to the curve at x = -1
c. deduce the gradient of the tangent to the curve at the point where x = -1
no idea how to do part b and c
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(1√6 - 2√9+3√4)/(9√4-4√9)
How would this be simplified?
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Sxc avatar made by a sxc person: carrotontheground http://community.boredofstudies.org/...otontheground/
is 3/(x-1)+2 a polynomial ? If no, why isn't it a polynomial?
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ATAR: 36.85 | TAFE Diploma of Technical Engineering @ Mt Druitt Campus
thanks
for the help
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Last edited by pikachu975; 1 Jun 2017 at 5:50 PM.
2016 HSC (Accelerated)
// 2 Unit Maths // Studies of Religion 1 //
2017 HSC
// Biology // Physics // Maths Extension 1 // Maths Extension 2 // English Advanced //
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ATAR: 36.85 | TAFE Diploma of Technical Engineering @ Mt Druitt Campus
How would you show that the points (5,2). (-2,1) and (1,5) form the vertices of an isosceles triangle?
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all of the points (-1,-6), (0,-6), (1,-2) and (2,2) lie on the cubic with equation ax^3 + bx^2 + cx + d.
Find the value of d
determine 3 simultaneous equations that will enable solutions to a, b, and c to be found
find the values of a, b, and c, and determine the equation of the cubic
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a graph has the rule
y = a/(x-b)^2 + c
the y intercept is located ta (0,-1) and an asymptote exists at y = 2, determine the values of a, b, and c
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Would appreciate any help. Have a maths exam in 4 days
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If f(x) = 3x and g(x) = x+2, then what is the value of g(f(-1))
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