1. Re: VCE Maths questions help

Originally Posted by InteGrand
4
How do you work it out?

2. Re: VCE Maths questions help

Originally Posted by boredsatan
How do you work it out?
It's the slope of the tangent at the given point (and we're given that tangent's equation (we're given that the line is tangent)).

3. Re: VCE Maths questions help

Originally Posted by InteGrand
It's the slope of the tangent at the given point (and we're given that tangent's equation (we're given that the line is tangent)).
so the gradient of 4x-4 which is 4

4. Re: VCE Maths questions help

Originally Posted by boredsatan
so the gradient of 4x-4 which is 4
Yep

5. Re: VCE Maths questions help

Originally Posted by Squar3root
Yep
thanks

6. Re: VCE Maths questions help

how would you find f'(1) for f(x) = 5x

7. Re: VCE Maths questions help

Originally Posted by boredsatan
how would you find f'(1) for f(x) = 5x
Note f'(x) = 5 for all x, so f'(1) = 5.

8. Re: VCE Maths questions help

What is this? boredsatan's do my maths homework and sanity check thread?

Most of the time, you don't show appreciation for help you receive... and even dare to ignore some solutions.

This thread is more harm than good; it's an obstacle that lessens the opportunities for you to exercise your own judgement.

9. Re: VCE Maths questions help

He is not the only one. Many on BOS posed questions and mostly made no acknowledgement nor words of appreciation. I suppose that is the norm of the current generation.

10. Re: VCE Maths questions help

Originally Posted by He-Mann
What is this? boredsatan's do my maths homework and sanity check thread?

Most of the time, you don't show appreciation for help you receive... and even dare to ignore some solutions.

This thread is more harm than good; it's an obstacle that lessens the opportunities for you to exercise your own judgement.
Is there a problem with not being that good at maths?

11. Re: VCE Maths questions help

Originally Posted by boredsatan
Is there a problem with not being that good at maths?
No

Originally Posted by He-Mann
Most of the time, you don't show appreciation for help you receive... and even dare to ignore some solutions.

12. Re: VCE Maths questions help

Originally Posted by He-Mann
What is this? boredsatan's do my maths homework and sanity check thread?

Most of the time, you don't show appreciation for help you receive... and even dare to ignore some solutions.

This thread is more harm than good; it's an obstacle that lessens the opportunities for you to exercise your own judgement.
If I say thank you every time, won't it count as shitposting?

13. Re: VCE Maths questions help

Originally Posted by boredsatan
If I say thank you every time, won't it count as shitposting?
Why would it be considered as 'shitposting'?

There are other ways to express gratitude other than words. Imagine you and a group of kind helpers spare some time out of multiple days to help a struggling homeless person and that person just takes your gifts without making eye contact, rarely expresses gratitude, begs for more... How would you feel?

Also, I'm not making the comments based on my views on your ability to do maths but it's because I've noticed you've become dependent on this thread to do some maths. How will you handle yourself when there is no help?

14. Re: VCE Maths questions help

Originally Posted by boredsatan
If I say thank you every time, won't it count as shitposting?
I think another thing He-Mann said in the last line was to try questions yourself before posting, e.g. derivative of 5x

15. Re: VCE Maths questions help

Alot of the time I do try the questions myself but still find it hard

16. Re: VCE Maths questions help

Originally Posted by boredsatan
Alot of the time I do try the questions myself but still find it hard
Hello there, just wondering, how is finding the derivative of 5x hard?

17. Re: VCE Maths questions help

Originally Posted by -s-
Hello there, just wondering, how is finding the derivative of 5x hard?
i didn't ask to find the derivative of 5x, i asked this
"how would you find f'(1) for f(x) = 5x"

18. Re: VCE Maths questions help

Originally Posted by boredsatan
i didn't ask to find the derivative of 5x, i asked this
"how would you find f'(1) for f(x) = 5x"
f'(x) is a derivative so it's pretty much differentiating 5x

19. Re: VCE Maths questions help

Originally Posted by pikachu975
f'(x) is a derivative so it's pretty much differentiating 5x
if you say so

20. Re: VCE Maths questions help

Originally Posted by boredsatan
Alot of the time I do try the questions myself but still find it hard
Originally Posted by boredsatan
how would you find f'(1) for f(x) = 5x
even though i am 99.9% sure you're a troll but for that 0.1% of doubt, im gonna be honest; if you find these basic questions "hard" you should really consider dropping math or dropping down to general maths. It won't do anything good for your atar if you get 50 in 2U versus getting 65+ in general

21. Re: VCE Maths questions help

r(x) = -200x^2 + 4800x
find r(x+h)
-200x^2 - 400xh -200h^2 + 4800x + 4800h
use differenetiation by first principles to find the equation of the rate of change in revenue respect to the month of the year
-400x + 4800
find the instantaneous rate of change in revenue at B (6,21600)
-400(6) + 4800 = 2400
find the equation of the tangent to the revenue at C (10,28000)
-400(10) + 4800 = -4000 + 4800 = 800
y = 800x + c
28000 = 800(10) + c
y = 800x + 20,000

2. p(x) = x^3 - 4x + 2
find p'(x)
3x^2 - 4
find p'(3)
3(3)^2 - 4 = 27-4 = 23
find the equation of the perpendicular line to p(x) at x = 3
p(3) = (3)^3 - 4(3) + 2 = 17
(3,17)
p'(3) = 3(3)^2 - 4 = 27-4 = 23
m1*m2 = -1
m1*23 = -1
m1 = -1/23
17 = -1/23(3) + c
c = 394/23
y = -1/23x + 394/23
use newton's methods to calculate the root of the equation x^3 - 4x + 2 = 0 that lies near x = 3. Express the answer correct to 3 decimal places

3. c(x) = (x^3 - 9x^2 + 26x - 24)/(x-3)
is the function continuous?
Yes, the function is continuous as it is drawn without lifting the pen of paper
calculate lim x (3) for c(x)
(x^3 - 9x^2 + 26x - 24)/(x-3) = (x-2)(x-3)(x-4)/(x-3)
= (x-2)(x-4)
= (3-2)(3-4)
= 1 * -1
= -1

4. The rate of change is expressed by s'(t) = 3x^2 - 36x + 72, x [0,12]. Find an expression for the total inventory, s(t) if the company had 200 items initially
6x - 36 + 200
b. Determine the area bounded by s'(t) and the x-axis between 2.54 ≤ t ≤ 9.46, correct to 2 decimal places
using calculus, 166.28
using the graph of the gradient, draw a sketch of a possible curve of s(t), label turning points, end points and intercepts

22. Re: VCE Maths questions help

Any help will be greatly appreciated. Have a test this friday

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25. Re: VCE Maths questions help

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