why is cos (-pi/4) the same as cos (pi/4)?
evaluate tan (2pi/3)
= (3pi/3) - (pi/3)
=(pi) - (pi/3)
=+ tan (pi/3) = (√3)
Is this correct?
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why is cos (-pi/4) the same as cos (pi/4)?
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The first four quadrants are positive for cos. (pi/4) is obviously in the first quadrant, and if you can see that (-pi/4) is actually in the fourth quadrant, then both cos(pi/4) and cos(-pi/4) are positive (1/√2). It might not be the best explanation because this is much easier to show with a diagram of the quadrants, but I hope it helps anyway.
2017 HSC:: English Adv - Maths Ext 1 - Maths Ext 2 - Chemistry - Physics
2017 ATAR: 93.6 (screw English)
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If pr(A) = 0.45, pr(B) = 0.35, and pr(A inverted u B) = 0.25, how would you find Pr (A' inverted u B')
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convert 7pi/12 to degrees
(7pi/12)*(180/pi)
=1260pi/12pi
= 105
is this correct?
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Anyone know how to work out tan (5pi/4) as i'm really confused?
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bump
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How would you work out tan (-2pi/3)
I'm confused as it's negative
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in a population of 10,000 people, 75% spoke german, 45% spoke french, and 10% of the population did not speak either french or german
draw a venn diagram
how do you work out how many people speak both french and german, given that it's not stated above?
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solve cos(x) = 0.5, (-4pi to 4pi)
base = pi/3,
+ve rotation
x = pi/3, 2pi-pi/3 = 5pi/3
pi/3 + 2pi = 7pi/3
5pi/3 + 2pi = 11pi/3
-ve rotation
x = -pi/3, x = -2pi + pi/3 = -5pi/3
-2pi - (-pi/3) = -5pi/3
-2pi - (-5pi/3) = -pi/3
are these answers right?
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A is a matrix of order (3*5) and the order of the matrix product AB is (3*1) then what is the order of matrix B? How would you work it out?
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Remember, the general rule is if A is (m x n) and B is (n x p), then AB is (m x p).
Since A is (3 x 5) and AB is (3 x 1), we must have that B is (5 x 1). (No. of rows of B must be 5 in order for B to be compatible with A in the product AB, and no. of columns of B must be 1 in order that the no. of columns in the result AB is 1.)
2^x = 7
How would you solve for x without a calculator using logarithms?
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