f(x) = sqrt(x+1), and has a restricted domain of [0, infinity)
g(x) = x^2+4x+3, and has a restricted domain of (-infinity, -3]
How would i find the range of f(g(x)) without a calculator?
f(x) = sqrt(x+1), and has a restricted domain of [0, infinity)
g(x) = x^2+4x+3, and has a restricted domain of (-infinity, -3]
How would i find the range of f(g(x)) without a calculator?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
Is the square root of 4 just 2 or both 2 and -2?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
Bump
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
Square rooting is usually principal root, so omly +ve case
Is this always the case that you only take the +ve?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
bump
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
bump
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
2sin(2x-pi/6) = 1 for a domain of -pi<x<pi
we multiply the domain values of 2, so it becomes -2pi<2x<2pi
but then do we subtract the domain values by -pi/6
or since 2sin(2x-pi/6) = 2sin(2(x-pi/12)), do we subtract the domain values by -pi/12?
Thanks
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
if we had to find the derivative of sqrt(x^2+3), and evaluate it when x = 1, we get 1/(sqrt(4)), which so in this case, would it be 1/2 and 1/-2?
or just 1/2?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
So in what cass is the square root both the +ve and -ve and in what cases is it only the +ve?
Also can someone please help me with the below questions?
2sin(2x-pi/6) = 1 for a domain of -pi<x<pi
we multiply the domain values of 2, so it becomes -2pi<2x<2pi
but then do we subtract the domain values by -pi/6
or since 2sin(2x-pi/6) = 2sin(2(x-pi/12)), do we subtract the domain values by -pi/12?
Thanks
f(x) = sqrt(x+1), and has a restricted domain of [0, infinity)
g(x) = x^2+4x+3, and has a restricted domain of (-infinity, -3]
How would i find the range of f(g(x)) without a calculator?
f(g(x)) = sqrt(x^2+4x+4), so would I use the domain of g(x) as the domain of f(g(x))?
year 11 2017
year 12 2018
year boredsatan 2019
year LOL 2020-infinity
There are currently 1 users browsing this thread. (0 members and 1 guests)
Bookmarks