# Thread: VCE Maths questions help

1. ## Re: VCE Maths questions help

Assuming the natural domain; i.e. largest set of values of x that is allowed. For this question, where presumably we are dealing with a real function, it is all real values except x = -2; when x = -2, you will have a division by zero - which is a Cardinal sin in maths. The corresponding range is all y > 2; i.e. all real numbers greater than 2.  Reply With Quote

2. ## Re: VCE Maths questions help Originally Posted by Drongoski Assuming the natural domain; i.e. largest set of values of x that is allowed. For this question, where presumably we are dealing with a real function, it is all real values except x = -2; when x = -2, you will have a division by zero - which is a Cardinal sin in maths. The corresponding range is all y > 2; i.e. all real numbers greater than 2.
is there any other domain possible?  Reply With Quote

3. ## Re: VCE Maths questions help Originally Posted by boredsatan is there any other domain possible?
Yes. What Drongoski gave is the natural domain (assuming we are dealing with functions of a real variable). You can read up about this here: https://en.wikipedia.org/wiki/Domain...Natural_domain .  Reply With Quote

4. ## Re: VCE Maths questions help

How should I prepare for my maths application task, which is in a week.?  Reply With Quote

5. ## Re: VCE Maths questions help Originally Posted by boredsatan How should I prepare for my maths application task, which is in a week.?
any thoughts?  Reply With Quote

6. ## Re: VCE Maths questions help Originally Posted by boredsatan any thoughts?
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.  Reply With Quote

7. ## Re: VCE Maths questions help

y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right  Reply With Quote

8. ## Re: VCE Maths questions help Originally Posted by jathu123 Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.
Will doing chapter review from the textbook be beneficial  Reply With Quote

9. ## Re: VCE Maths questions help Originally Posted by boredsatan Will doing chapter review from the textbook be beneficial
yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good idea  Reply With Quote

10. ## Re: VCE Maths questions help Originally Posted by boredsatan y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
Anyone?  Reply With Quote

11. ## Re: VCE Maths questions help Originally Posted by boredsatan y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right Originally Posted by boredsatan Anyone?
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)  Reply With Quote

12. ## Re: VCE Maths questions help Originally Posted by InteGrand The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)
How would the range be written as?  Reply With Quote

13. ## Re: VCE Maths questions help Originally Posted by boredsatan How would the range be written as?
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?  Reply With Quote

14. ## Re: VCE Maths questions help Originally Posted by InteGrand You said the range is all real numbers excluding 2. But this is not correct. Can you see why?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?  Reply With Quote

15. ## Re: VCE Maths questions help Originally Posted by boredsatan I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?  Reply With Quote

16. ## Re: VCE Maths questions help Originally Posted by leehuan So what would the actual range be?  Reply With Quote

17. ## Re: VCE Maths questions help

How do you graph y = c?  Reply With Quote

18. ## Re: VCE Maths questions help Originally Posted by boredsatan How do you graph y = c?
Horizontal line through the point (0, c).

(Where the x-axis is the horizontal axis and the y-axis is the vertical axis, as usual.)  Reply With Quote

19. ## Re: VCE Maths questions help Originally Posted by boredsatan So what would the actual range be?
If you can't tell by inspection, better sketch it  Reply With Quote

20. ## Re: VCE Maths questions help Originally Posted by leehuan could it be (2,infinity), even though the graph never touches 2?  Reply With Quote

21. ## Re: VCE Maths questions help Originally Posted by boredsatan could it be (2,infinity), even though the graph never touches 2?
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.  Reply With Quote

22. ## Re: VCE Maths questions help Originally Posted by InteGrand Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on  Reply With Quote

23. ## Re: VCE Maths questions help Originally Posted by boredsatan so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Would it be open brackets around both 2 and infinity?  Reply With Quote

24. ## Re: VCE Maths questions help Originally Posted by boredsatan so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yes  Reply With Quote

25. ## Re: VCE Maths questions help Originally Posted by boredsatan Would it be open brackets around both 2 and infinity?
Yes (for y = 2/[(x+2)2] + 2).  Reply With Quote