# Thread: VCE Maths questions help

1. ## Re: VCE Maths questions help

Assuming the natural domain; i.e. largest set of values of x that is allowed. For this question, where presumably we are dealing with a real function, it is all real values except x = -2; when x = -2, you will have a division by zero - which is a Cardinal sin in maths. The corresponding range is all y > 2; i.e. all real numbers greater than 2.

2. ## Re: VCE Maths questions help

Originally Posted by Drongoski
Assuming the natural domain; i.e. largest set of values of x that is allowed. For this question, where presumably we are dealing with a real function, it is all real values except x = -2; when x = -2, you will have a division by zero - which is a Cardinal sin in maths. The corresponding range is all y > 2; i.e. all real numbers greater than 2.
is there any other domain possible?

3. ## Re: VCE Maths questions help

Originally Posted by boredsatan
is there any other domain possible?
Yes. What Drongoski gave is the natural domain (assuming we are dealing with functions of a real variable). You can read up about this here: https://en.wikipedia.org/wiki/Domain...Natural_domain .

4. ## Re: VCE Maths questions help

How should I prepare for my maths application task, which is in a week.?

5. ## Re: VCE Maths questions help

Originally Posted by boredsatan
How should I prepare for my maths application task, which is in a week.?
any thoughts?

6. ## Re: VCE Maths questions help

Originally Posted by boredsatan
any thoughts?
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.

7. ## Re: VCE Maths questions help

y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

8. ## Re: VCE Maths questions help

Originally Posted by jathu123
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.
Will doing chapter review from the textbook be beneficial

9. ## Re: VCE Maths questions help

Originally Posted by boredsatan
Will doing chapter review from the textbook be beneficial
yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good idea

10. ## Re: VCE Maths questions help

Originally Posted by boredsatan
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
Anyone?

11. ## Re: VCE Maths questions help

Originally Posted by boredsatan
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
Originally Posted by boredsatan
Anyone?
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)

12. ## Re: VCE Maths questions help

Originally Posted by InteGrand
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)
How would the range be written as?

13. ## Re: VCE Maths questions help

Originally Posted by boredsatan
How would the range be written as?
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?

14. ## Re: VCE Maths questions help

Originally Posted by InteGrand
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

15. ## Re: VCE Maths questions help

Originally Posted by boredsatan
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?
$\text{Look carefully. It's }\frac{2}{(x+2)^\textbf{2}}+2\\ \text{You've stated the range of }\frac{2}{x+2}+2\text{ without the power of 2. This is not a hyperbola.}$

16. ## Re: VCE Maths questions help

Originally Posted by leehuan
$\text{Look carefully. It's }\frac{2}{(x+2)^\textbf{2}}+2\\ \text{You've stated the range of }\frac{2}{x+2}+2\text{ without the power of 2. This is not a hyperbola.}$
So what would the actual range be?

17. ## Re: VCE Maths questions help

How do you graph y = c?

18. ## Re: VCE Maths questions help

Originally Posted by boredsatan
How do you graph y = c?
Horizontal line through the point (0, c).

(Where the x-axis is the horizontal axis and the y-axis is the vertical axis, as usual.)

19. ## Re: VCE Maths questions help

Originally Posted by boredsatan
So what would the actual range be?
If you can't tell by inspection, better sketch it

20. ## Re: VCE Maths questions help

could it be (2,infinity), even though the graph never touches 2?

21. ## Re: VCE Maths questions help

Originally Posted by boredsatan
could it be (2,infinity), even though the graph never touches 2?
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.

22. ## Re: VCE Maths questions help

Originally Posted by InteGrand
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

23. ## Re: VCE Maths questions help

Originally Posted by boredsatan
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Would it be open brackets around both 2 and infinity?

24. ## Re: VCE Maths questions help

Originally Posted by boredsatan
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yes

25. ## Re: VCE Maths questions help

Originally Posted by boredsatan
Would it be open brackets around both 2 and infinity?
Yes (for y = 2/[(x+2)2] + 2).

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