Page 1 of 13 12311 ... LastLast
Results 1 to 25 of 306
Like Tree20Likes

Thread: VCE Maths questions help

  1. #1
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    VCE Maths questions help

    1. How to find the turning point and type of turning point in the equation y = (2/3)x^4 + 1/3
    2. how to find equation of axis of symmetry of y = (2/3)x^4 + 1/3

  2. #2
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    1. How to find the turning point and type of turning point in the equation y = (2/3)x^4 + 1/3
    2. how to find equation of axis of symmetry of y = (2/3)x^4 + 1/3
    1) Turning point at 0, local minimum.

    2) Axis of symmetry is the y-axis.

    Method used: inspection.

  3. #3
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    2) My book said that the axis of symmetry is x = 0. Maybe my book's wrong?

  4. #4
    New Member
    Join Date
    Jan 2017
    HSC
    2017
    Gender
    Undisclosed
    Posts
    5
    Rep Power
    1

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    2) My book said that the axis of symmetry is x = 0. Maybe my book's wrong?

    the y axis is x=0!!!
    four units of english | three units of maths | physics | chemystery | PDHPE

  5. #5
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Quote Originally Posted by disturb_equilibrium View Post
    the y axis is x=0!!!
    Oh, right, I get it now, was just a bit confused before.

  6. #6
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    What's the difference between the turning point and the stationary point of inflection?

  7. #7
    Hi Φ Rathin's Avatar
    Join Date
    Mar 2015
    HSC
    2017
    Gender
    Male
    Posts
    2,686
    Rep Power
    3

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    What's the difference between the turning point and the stationary point of inflection?
    A point where a function changes from an increasing to a decreasing function or visa-versa is known as a turning point (i.e. gradient =0) However with turning points the concavity remains the same. In a stationary point of inflexion the gradient is 0 but the concavity changes, thus not changing from an increasing to a decreasing function or visa-versa.
    2016 Preliminary

    Maths Extension • English Advanced • Biology • Legal Studies • Physics • PDHPE

    2017 HSC

    Maths Extension 2 • English Advanced • Biology • Physics • PDHPE

    Atar aim: 97
    Desired Course: Physiotherapy

  8. #8
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Quote Originally Posted by Rathin View Post
    A point where a function changes from an increasing to a decreasing function or visa-versa is known as a turning point (i.e. gradient =0) However with turning points the concavity remains the same. In a stationary point of inflexion the gradient is 0 but the concavity changes, thus not changing from an increasing to a decreasing function or visa-versa.
    So for x^2, x^4, x^6, x^8, etc, there's a turning point, and for x^3, x^5, x^7, x^9, etc there's a stationary point of inflection?

  9. #9
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    So for x^2, x^4, x^6, x^8, etc, there's a turning point, and for x^3, x^5, x^7, x^9, etc there's a stationary point of inflection?
    Correct!

  10. #10
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Quote Originally Posted by InteGrand View Post
    Correct!
    Thanks

  11. #11
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    How hard it to get raw 40 in vce maths methods?

  12. #12
    Loquacious One
    Join Date
    Feb 2009
    HSC
    N/A
    Gender
    Male
    Posts
    3,538
    Rep Power
    9

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    How hard it to get raw 40 in vce maths methods?
    Very few here are familiar with the VCE. But I find the VCE Maths curriculum modern and progressive.
    1-on-1 Maths Tutoring(IB & HSC): Epping, Beecroft, Eastwood, Carlingford & Beyond
    Highly Qualified & Highly Experienced. Estimated ATAR > 64.95
    There are IB Maths Tutors and there are IB Maths Tutors.

  13. #13
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Find the values of m if (2m-3)x^2 + (5m-1)x + (3m-2) = 0 has 2 solutions

  14. #14
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    Find the values of m if (2m-3)x^2 + (5m-1)x + (3m-2) = 0 has 2 solutions


    Remember, if the given quadratic equation has two distinct (real) solutions for x, then its discriminant must be greater than zero.

  15. #15
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Quote Originally Posted by InteGrand View Post


    Remember, if the given quadratic equation has two distinct (real) solutions for x, then its discriminant must be greater than zero.
    I ended up getting 25m^2 - 10m + 1 - 4(6m^2 - 13m + 6)
    = 25m^2 - 10m + 1 - 24m^2 + 52m - 24
    = m^2 + 42m - 23 > 0

  16. #16
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    I ended up getting 25m^2 - 10m + 1 - 4(6m^2 - 13m + 6)
    = 25m^2 - 10m + 1 - 24m^2 + 52m - 24
    = m^2 + 42m - 23 > 0

  17. #17
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    A piece of wire 12 cm long is cut into two pieces. One piece is used to form a square shape and the other a rectangle shape in which the length is twice the width.
    a. If x cm is the side length of the square, write down the dimensions of the rectangle in terms of x
    b. formulate a rule for A, the combined area of the square and rectangle in cm^2, in terms of x.
    c. determine the lengths of the two pieces if the sum of the areas is to be a minimum.

  18. #18
    Member kawaiipotato's Avatar
    Join Date
    Apr 2015
    HSC
    2015
    Gender
    Undisclosed
    Posts
    442
    Rep Power
    2

    Re: maths questions help







    Last edited by kawaiipotato; 29 Apr 2017 at 9:45 PM.
    Sxc avatar made by a sxc person: carrotontheground http://community.boredofstudies.org/...otontheground/

  19. #19
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Is it normal to find maths hard even after tution? I'm in this scenario

  20. #20
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    The graph of y = x^4 - 2x - 12 has 2 x-intercepts
    a. construct a table of values for this polynomial rule for x = -3,-2,-1,0,1,2,3
    b. Hence state an exact solution to the equation x^4 - 2x - 12 = 0
    c. State an interval within which the other root of the equation lies and use the methods of bisection to obtain an estimate of this root correct to 1 decimal place

    I get how to do part a and b, but i'm finding part c extremely challenging and confusing.

  21. #21
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    The graph of y = x^4 - 2x - 12 has 2 x-intercepts
    a. construct a table of values for this polynomial rule for x = -3,-2,-1,0,1,2,3
    b. Hence state an exact solution to the equation x^4 - 2x - 12 = 0
    c. State an interval within which the other root of the equation lies and use the methods of bisection to obtain an estimate of this root correct to 1 decimal place

    I get how to do part a and b, but i'm finding part c extremely challenging and confusing.
    If you know a place where the polynomial is positive and another place where it is negative (and the root you already found does not lie between these two places), then the other root lies between these two numbers. You can then use the bisection method (check your textbook if you haven't learnt it yet).

  22. #22
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    I read my textbook but I still don't understand the bisection methods.

  23. #23
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    I read my textbook but I still don't understand the bisection methods.
    Are there any examples in the textbook using bisection method? See this page if not (there's an example in it): https://en.wikipedia.org/wiki/Bisection_method .
    kawaiipotato likes this.

  24. #24
    Member boredsatan's Avatar
    Join Date
    Mar 2017
    HSC
    1998
    Gender
    Male
    Posts
    430
    Rep Power
    1

    Re: maths questions help

    Can someone please help?
    The graph of y = x^4 - 2x - 12 has 2 x-intercepts
    a. construct a table of values for this polynomial rule for x = -3,-2,-1,0,1,2,3
    b. Hence state an exact solution to the equation x^4 - 2x - 12 = 0
    c. State an interval within which the other root of the equation lies and use the methods of bisection to obtain an estimate of this root correct to 1 decimal place

    I get how to do part a and b, but i'm finding part c extremely challenging and confusing.

  25. #25
    Ancient Orator
    Join Date
    Dec 2014
    HSC
    N/A
    Gender
    Male
    Posts
    5,881
    Rep Power
    5

    Re: maths questions help

    Quote Originally Posted by boredsatan View Post
    Can someone please help?
    The graph of y = x^4 - 2x - 12 has 2 x-intercepts
    a. construct a table of values for this polynomial rule for x = -3,-2,-1,0,1,2,3
    b. Hence state an exact solution to the equation x^4 - 2x - 12 = 0
    c. State an interval within which the other root of the equation lies and use the methods of bisection to obtain an estimate of this root correct to 1 decimal place

    I get how to do part a and b, but i'm finding part c extremely challenging and confusing.
    Quote Originally Posted by InteGrand View Post
    If you know a place where the polynomial is positive and another place where it is negative (and the root you already found does not lie between these two places), then the other root lies between these two numbers. You can then use the bisection method (check your textbook if you haven't learnt it yet).
    .

Page 1 of 13 12311 ... LastLast

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •