Second Derivative Help (1 Viewer)

billjyang · Jul 2, 2017

Hey Guys!
why cant a point of inflection occur at (d^3y)/(dx^3) = 0

InteGrand · Jul 2, 2017

billjyang said:
Hey Guys!
why cant a point of inflection occur at (d^3y)/(dx^3) = 0

It can – consider y = x^5 at the origin.

1729 · Jul 2, 2017

billjyang said:
Hey Guys!
why cant a point of inflection occur at (d^3y)/(dx^3) = 0

$$\noindent It can. If $y = x^5$ then $\frac{d^3y}{dx^3} = 60x^2$. If $\frac{d^3y}{dx^3} = 0$ then $x = 0$. And at $x = 0$ there is a point of inflexion on $y = x^5$.$

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Second Derivative Help (1 Viewer)

billjyang

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InteGrand

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1729

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