1)a) Arrangements: 5! and 2 repetitions of 4, hence 5!/2! = 60

b) Not sure how to do the rest of the parts but I think just use cases. Hopefully someone like Integrand or Drongoski answers

2) There's only one scenario with CAL, and for the denominator, the ways to pick letters = 8C3, therefore 1/56

## Bookmarks