Trig (1 Viewer)

highshill

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Does anyone know how to solve this with working out
find theta
sectheta=3
Thanks
 

Sp3ctre

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secθ=3
1/secθ = 1/3
cosθ = 1/3

If you're not doing extension 1 maths, then the solution via general formula (the final answer 1729 posted) will probably not make sense to you. Depending on the domain, just solve θ like a normal trig equation. Assuming they only want the answer for the first quadrant, it would be

θ = cos^-1(1/3)
θ = 70 degrees, 32 minutes or 1.23... radians
 

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