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Thread: Feeling retarded ATM

  1. #1
    Exalted Member hayabusaboston's Avatar
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    Feeling retarded ATM

    Havent been following lectures and now don't know what these mean, question 1 the "express as..." part

    http://imgur.com/a/HckCP

    Can someone just do the first one and I'll understand how to do the rest? I known how to show is or isn't subspace just evoressing as set of vectors idk maybe I'm retarded
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    Exalted Member hayabusaboston's Avatar
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    Re: Feeling retarded ATM

    Oh and determine if subspace of R^n means the subsists of R^(number of vectors) right??
    Quote Originally Posted by asianese View Post
    Nah he's (hayabusaboston) like, God, so listen to him.
    2013 ATAR: 94.55
    Besmirch me now, for thou protectress deem it right.


    YES I LOVE MYSELF AND MY BODY BECAUSE IM BEAUTIFUL LIKE ANY OTHER FAT GIRL OR SKINNY GIRL

    But im a boy. So there's a difference.

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    Re: Feeling retarded ATM

    Hi there,

    I'm not sure if you still need help with this as it has been over a month since you asked, but 1a is not closed under scaler multiplication and hence is not a subspace. 1b and c are similarly, not subspaces (I'll leave it to you to figure out why). 1d is a subspace (you can check all 3 defining axioms yourself). To express this as a span of vectors, consider a general vector in R^3, (a,b,c). We know that

    a + b + c = 0 ... (1) and
    a + b - c = 0 ... (2)

    (1)-(2) gives
    2c =0 => c = 0

    and hence
    a + b = 0 => a = -b

    We can go back and write our general vector as (-b,b,0) which is the same as span{(-1,1,0)}.

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