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Thread: james ruse 2008 year 10 yearly paper

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    Question james ruse 2008 year 10 yearly paper

    can anyone explain Q.28 from james ruse 2008 year 10 yearly paper?
    https://thsconline.github.io/s/?view...008%20w.%20sol

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    Re: james ruse 2008 year 10 yearly paper

    AB^2 = BD * BC (square of intercept on tangent equals product of intercepts on secant)
    AB^2 = 7 * 2
    AB^2 = 14

    Therefore, AB = sqroot 14 (length > 0).
    The answer's B.

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