how do you sketch f"(x) from f'(x) (1 Viewer)

highshill

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So do we follow the same principle :
f'(x) to f(x)
Find Stationary Point
if line/curve is above the x-axis the gradient is positive and if the graph is below the gradient is negative
Sketch according to slope

So for f'(x) to f"(x)
Same thing :)
 

captainhelium

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So do we follow the same principle :
f'(x) to f(x)
Find Stationary Point
if line/curve is above the x-axis the gradient is positive and if the graph is below the gradient is negative
Sketch according to slope

So for f'(x) to f"(x)
Same thing :)
Yeah its the same process as sketching f(x) to f'(x).

- Stationary points become x-intercepts
- Parts with a positive gradient are above the x axis
- Parts with a negative gradient are below the x axis
 

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