enigma_1
~~~~ Miss Cricket ~~~~
Stuck on this question 
A particular brand of 'cloudy ammonia' cleaner claims on the label 'not to contain more than 8% ammonia by volume' (that is 8% w/v).
To investigate this claim, a 11.3451-g sample of the cloudy ammonia solution (density = 0.94437 g/mL) was added to a 200.0-mL volumetric flask, and carefully made up to the mark, with thorough mixing, using distilled water. 25.00-mL aliquots of this solution were titrated with 0.3319 M HCl and an average titre of 21.21 mL of the acid was required to reach the end point. One mole of ammonia reacts with 1 mole of HCl at the end-point.
From these results, calculate the concentration of NH3 in %w/v in the cloudy ammonia solution.
How do I do this?
Thanks
A particular brand of 'cloudy ammonia' cleaner claims on the label 'not to contain more than 8% ammonia by volume' (that is 8% w/v).
To investigate this claim, a 11.3451-g sample of the cloudy ammonia solution (density = 0.94437 g/mL) was added to a 200.0-mL volumetric flask, and carefully made up to the mark, with thorough mixing, using distilled water. 25.00-mL aliquots of this solution were titrated with 0.3319 M HCl and an average titre of 21.21 mL of the acid was required to reach the end point. One mole of ammonia reacts with 1 mole of HCl at the end-point.
From these results, calculate the concentration of NH3 in %w/v in the cloudy ammonia solution.
How do I do this?
Thanks
