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Thread: First Year Mathematics A (Differentiation & Linear Algebra)

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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    So knowing the definition of a continuous function, can you just say since the its lim = 0 from both the left and right hand side, it is continuous since as x->a f(x) = f(a).

    Would writing just that be acceptable as an answer instead of using the eps-delta method?
    Idk, by saying that the limits are 0 from the left and right, it seems (in my opinion) too close to assuming what they're asking you to prove.

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    Ancient Orator leehuan's Avatar
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    Re: MATH1131 help thread

    They defined continuity for us somewhere along the lines of this


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    Re: MATH1131 help thread

    (a) Show that if A is a 2 × 2 matrix, and its two rows are identical, then det(A) = 0.

    (b) Prove by induction that if A is an n × n matrix which has two identical rows, then det(A) = 0.
    [Hint: expand along one of the other rows].



    How would one approach this question? Part a is quite easy, though I am not sure about part b.

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    Re: MATH1131 help thread

    Quote Originally Posted by turntaker View Post
    (a) Show that if A is a 2 × 2 matrix, and its two rows are identical, then det(A) = 0.

    (b) Prove by induction that if A is an n × n matrix which has two identical rows, then det(A) = 0.
    [Hint: expand along one of the other rows].



    How would one approach this question? Part a is quite easy, though I am not sure about part b.
    |a al
    |b bl = ab-ba
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    Re: MATH1131 help thread

    Quote Originally Posted by iforgotmyname View Post
    |a al
    |b bl = ab-ba
    that's part a :P

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    Re: MATH1131 help thread

    Quote Originally Posted by turntaker View Post
    (a) Show that if A is a 2 × 2 matrix, and its two rows are identical, then det(A) = 0.

    (b) Prove by induction that if A is an n × n matrix which has two identical rows, then det(A) = 0.
    [Hint: expand along one of the other rows].



    How would one approach this question? Part a is quite easy, though I am not sure about part b.






    (Parity of an integer refers to whether it is odd or even.)
    Last edited by InteGrand; 24 Apr 2016 at 10:49 AM.

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    Supreme Member Flop21's Avatar
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    Re: MATH1131 help thread

    Okay so with parametric vector forms of lines...

    I was under the impression it was x = a + lambda(v). And I though V was simply AB (given two points A and B), so to get the vector you go B-A.

    But in the solutions for my practice test it has A-B. Why have they got this, and if that is correct, why?
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    Okay so with parametric vector forms of lines...

    I was under the impression it was x = a + lambda(v). And I though V was simply AB (given two points A and B), so to get the vector you go B-A.

    But in the solutions for my practice test it has A-B. Why have they got this, and if that is correct, why?
    Doesn't matter. Let mu = -lambda and donezo

    Convention is to use B-A because A-B is technically a negative case

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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    Okay so with parametric vector forms of lines...

    I was under the impression it was x = a + lambda(v). And I though V was simply AB (given two points A and B), so to get the vector you go B-A.

    But in the solutions for my practice test it has A-B. Why have they got this, and if that is correct, why?

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    Supreme Member Flop21's Avatar
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    Re: MATH1131 help thread

    Quote Originally Posted by InteGrand View Post
    Oh right, because you can have multiple parametric vector forms for the same line? Because I was getting the signs of my vectors opposite to the answers (since they used A-B).
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    Oh right, because you can have multiple parametric vector forms for the same line? Because I was getting the signs of my vectors opposite to the answers (since they used A-B).
    Yes, the parametric vector form for a given line is not unique. This is why we sometimes say "a" parametric form rather than "the" parametric form.
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    Re: MATH1131 help thread

    FML

    I'm falling behind in maths. I need to catch up on lectures I've missed (due to catching up), but have trouble attending lectures since I don't understand what's going on because I've missed lectures / haven't had time to revise and understand.

    So little time for anything tbh.

    It's like a horrible cycle that I can't get out of, any advice anyone?
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    FML

    I'm falling behind in maths. I need to catch up on lectures I've missed (due to catching up), but have trouble attending lectures since I don't understand what's going on because I've missed lectures / haven't had time to revise and understand.

    So little time for anything tbh.

    It's like a horrible cycle that I can't get out of, any advice anyone?
    Surely you have lecture recordings on moodle

    But the course pack does a reasonable job at filling people in if you ask me

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    Supreme Member Flop21's Avatar
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    Re: MATH1131 help thread

    Quote Originally Posted by leehuan View Post
    Surely you have lecture recordings on moodle

    But the course pack does a reasonable job at filling people in if you ask me
    So I should skip this week's lectures as well and spend it catching up? I find myself prioritising studying for tests, so lately I've been just catching up on the upcoming test's material and not wanting to go ahead - but of course class is still speeding along with new crap while I study.


    Course pack is really good. Man can't wait to start over next sem, I've learned so much, but kind have stuffed this sem.
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    So I should skip this week's lectures as well and spend it catching up? I find myself prioritising studying for tests, so lately I've been just catching up on the upcoming test's material and not wanting to go ahead - but of course class is still speeding along with new crap while I study.


    Course pack is really good. Man can't wait to start over next sem, I've learned so much, but kind have stuffed this sem.
    In advance for the calculus test you probably want to focus on studying for that. Same for algebra. Then when no calculus test is coming up you should catch up on the calculus that you missed.

    But maths, well I view it as two seperate courses in algebra and calculus. You treat them seperate until final exam time.

    As for missing, well that's probably up to you

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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    FML

    I'm falling behind in maths. I need to catch up on lectures I've missed (due to catching up), but have trouble attending lectures since I don't understand what's going on because I've missed lectures / haven't had time to revise and understand.

    So little time for anything tbh.

    It's like a horrible cycle that I can't get out of, any advice anyone?
    If it makes you feel any better, I'm in the exact same boat for my subjects now

    And to compound it, my supervisor sent me an email, "Hey SD, how's the work going? Let's meet next week to discuss your project"


    catch is: i haven't done any work

    she's going to kill me
    B Arts / B Science (Advanced Mathematics), UNSW

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    Supreme Member Flop21's Avatar
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    Re: MATH1131 help thread

    Why is it when given some points after finding the cross product of vectors AB and AC, you find the result distance to find the area of the parallelogram?

    How does that give you the area of a parallelogram?
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    Why is it when given some points after finding the cross product of vectors AB and AC, you find the result distance to find the area of the parallelogram?

    How does that give you the area of a parallelogram?


    http://mathinsight.org/cross_product.
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    Supreme Member Flop21's Avatar
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    Re: MATH1131 help thread

    Okay can someone help me with finding the shortest distance d between a line and a point using vectors/projections??

    These questions come up a lot and I'm having trouble doing them, so if anyone could give me a general list of steps of what to do to solve these, that would be great.

    So say you get given a point - and it's said the line goes through that point, and is also parallel to a vector given, and you also get another point. They require you to find the projv/vector(the vector made by second point - first point).

    Now what do you do from here to find the shortest distance between the line and the second point??

    [if it would be easier for me to give a real example let me know]
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    Re: MATH1131 help thread

    I reckon draw a diagram and that'll help you out a lot - are you drawing pictures?
    B Arts / B Science (Advanced Mathematics), UNSW

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    Re: MATH1131 help thread

    Yeah but it's always so hard in 3D to actually look at the diagram and have it useful
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    Yeah but it's always so hard in 3D to actually look at the diagram and have it useful
    It suffices to draw a 2D diagram for that, even if the point and line are in some arbitrary n-dimensional space.

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    Re: MATH1131 help thread

    Quote Originally Posted by InteGrand View Post
    It suffices to draw a 2D diagram for that, even if the point and line are in some arbitrary n-dimensional space.
    do you mean drop the z number and just draw x and y?
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    Re: MATH1131 help thread

    Quote Originally Posted by Flop21 View Post
    do you mean drop the z number and just draw x and y?
    We just need to draw a rough diagram to see what projection vector to take and what lengths to use etc. So we don't need to worry about coordinates for our sketch. Just draw a line with the known point on the line, and the given point above the line, and see which projection vectors and lengths need to be taken.

    So basically pictures like in this link: https://en.wikipedia.org/wiki/Vector_projection .
    Last edited by InteGrand; 14 Apr 2016 at 11:55 AM.
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    Re: MATH1131 help thread

    If in 2014, the Australias population was 23 246 692, with a growth rate of approximately 1.14%, what was the population in 2015?

    Please help! What is the formula and how would you work out this question

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