Hi All,
I'm currently stuck on a logarithmic question that i've been attempting for most of an hour with 0 success. There are no answers releases yet & any help would be appreciated
Question below
My main point of confusion comes to what rule to apply first. Do i first have to solve Ln(10) & then isolate the logarithmic function by dividing the answer by 3?
Note that i need to find the value "x"
Last edited by Katsumi; 8 Mar 2017 at 10:19 PM.
Site Moderator: Business Studies, Community & Family Studies, Information Processes & Technology, Information Technology,University of Technology Sydney, All General Discussion Boards
Bachelor of Commerce (Finance & Banking) @ University of Sydney
Operations @ Big 4 Bank
If you know that x^{logxa} = a, then after dividing both sides by 3, x^{logx7} = x^{ln10/3}
So, 7 = x^{ln10/3}
Raising both sides by 3/ln10 gives x = 7^{3/ln10}
This is your first misunderstanding. You can't 'solve' ln10 - this is just a number, like the number 200, you can't solve just that number.
You will need to learn the log rules in order to solve any log problems. They are fundamental as they set the laws that govern what you can and can't do.
So this is the correct logic?
equation provided in question
3logx7 = ln10
a * logbc = logb(c^a)
logx7^3 = ln10
logbc=a is equal to b^a = c
x^ln10 = 7^3
isolate x by raising both sides to 1/x^ln10
x = (7^3)^1/ln10
Site Moderator: Business Studies, Community & Family Studies, Information Processes & Technology, Information Technology,University of Technology Sydney, All General Discussion Boards
Bachelor of Commerce (Finance & Banking) @ University of Sydney
Operations @ Big 4 Bank
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