# Thread: Logarithmic Question

1. ## Logarithmic Question

Hi All,

I'm currently stuck on a logarithmic question that i've been attempting for most of an hour with 0 success. There are no answers releases yet & any help would be appreciated

Question below My main point of confusion comes to what rule to apply first. Do i first have to solve Ln(10) & then isolate the logarithmic function by dividing the answer by 3?

Note that i need to find the value "x"  Reply With Quote

2. ## Re: Logarithmic Question Originally Posted by Katsumi Hi All,

I'm currently stuck on a logarithmic question that i've been attempting for most of an hour with 0 success. There are no answers releases yet & any help would be appreciated

Question below My main point of confusion comes to what rule to apply first. Do i first have to solve Ln(10) & then isolate the logarithmic function by dividing the answer by 3?  Reply With Quote

3. ## Re: Logarithmic Question

3*(logx(7))=ln(10)
logx(7^3)=ln(10)
logx(343)=ln(10)
x^(logx(343))=x^(ln(10))
343=x^(ln(10))
343^(1/ln(10))=(x^(ln(10))^(1/ln(10))
343^(1/ln(10))=x^((ln(10))*(1/ln(10))
343^(1/ln(10))=x^(1)
x=343^(1/ln(10))  Reply With Quote

4. ## Re: Logarithmic Question

If you know that xlogxa = a, then after dividing both sides by 3, xlogx7 = xln10/3

So, 7 = xln10/3

Raising both sides by 3/ln10 gives x = 73/ln10 Originally Posted by Katsumi Do i first have to solve Ln(10)
This is your first misunderstanding. You can't 'solve' ln10 - this is just a number, like the number 200, you can't solve just that number.

You will need to learn the log rules in order to solve any log problems. They are fundamental as they set the laws that govern what you can and can't do.  Reply With Quote

5. ## Re: Logarithmic Question

So this is the correct logic?

equation provided in question
3logx7 = ln10
a * logbc = logb(c^a)
logx7^3 = ln10
logbc=a is equal to b^a = c
x^ln10 = 7^3
isolate x by raising both sides to 1/x^ln10
x = (7^3)^1/ln10  Reply With Quote

6. ## Re: Logarithmic Question Originally Posted by Katsumi So this is the correct logic?

equation provided in question
3logx7 = ln10
a * logbc = logb(c^a)
logx7^3 = ln10
logbc=a is equal to b^a = c
x^ln10 = 7^3
isolate x by raising both sides to 1/x^ln10
x = (7^3)^1/ln10
Yep  Reply With Quote

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