delta x = Ux * t
1240 = Ux *(5)
Ux = 248 m/s
delta y = Uy*t - 1/2 *gt^2
0 = 5Uy - 1/2 * 9.8*25
Uy=24.5 m/s
So U = sqrt (Uy^2 + Ux^2)
U = 249.2072.. m/s
Find the angle use tantheta
A projectile has a range of 1240 metres and a flight time of 5 seconds. At what velocity is it projected?
delta x = Ux * t
1240 = Ux *(5)
Ux = 248 m/s
delta y = Uy*t - 1/2 *gt^2
0 = 5Uy - 1/2 * 9.8*25
Uy=24.5 m/s
So U = sqrt (Uy^2 + Ux^2)
U = 249.2072.. m/s
Find the angle use tantheta
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isn't the formula delta y=Uy*t + 1/2 *gt^2 and the answer you get for Uy=-24.5m/s which we in physics we can just change the negative when we want so the answer is Uy=24.5 m/s. Also, instead of using the displacement formula, can i use v=u+at where v=o, u=?, a=9.8 and t=5 to find uy?
Sorry, I didn't see you subbed in gravity -9.8, I thought u subbed in 9.8 sorry. However, am I able to use v=u+at to find uy?
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