V vustoxn New Member Joined May 23, 2008 Messages 15 Gender Undisclosed HSC 2009 Oct 30, 2008 #1 In the quadratic equation (K - 2)X^2 - 5X + 2K + 3 = 0 The roots are reciprocals of each other. Find the vale of K. The answer is ment to be K= -5 I dont understand how to solve the question... please help =]
In the quadratic equation (K - 2)X^2 - 5X + 2K + 3 = 0 The roots are reciprocals of each other. Find the vale of K. The answer is ment to be K= -5 I dont understand how to solve the question... please help =]
T Timothy.Siu Prophet 9 Joined Aug 6, 2008 Messages 3,449 Location Sydney Gender Male HSC 2009 Oct 30, 2008 #2 vustoxn said: In the quadratic equation (K - 2)X^2 - 5X + 2K + 3 = 0 The roots are reciprocals of each other. Find the vale of K. The answer is ment to be K= -5 I dont understand how to solve the question... please help =] Click to expand... let roots be a and 1/a a+1/a=5/(k-2) ax1/a=(2k+3)/(k-2)=1 2k+3=k-2 k=-5 ok, so u dont need the first equation
vustoxn said: In the quadratic equation (K - 2)X^2 - 5X + 2K + 3 = 0 The roots are reciprocals of each other. Find the vale of K. The answer is ment to be K= -5 I dont understand how to solve the question... please help =] Click to expand... let roots be a and 1/a a+1/a=5/(k-2) ax1/a=(2k+3)/(k-2)=1 2k+3=k-2 k=-5 ok, so u dont need the first equation
V vustoxn New Member Joined May 23, 2008 Messages 15 Gender Undisclosed HSC 2009 Oct 30, 2008 #3 Thank you so much! it had me fustrated! ^_^ thanks a bunch
