Maths Help (1 Viewer)

[Lemiixem]

I am having trouble finding the Length of AX. I have included an image of the diagram.

ABCD is a trapezium in which AB is parallel to DC. The diagonals intersect at X. AB=12cm, DC = 8cm and AC=10cm.

ii) Hence find the length of AX.

I have already proved that Triangle AXD is similar to Triangle CXD in the previous question.

 

[D94]

AX/12 = CX/8 by similar triangles. We also know that AC = AX + CX = 10. Then CX = 10 - AX.

Applying simultaneous equations, you have AX/12 = (10-AX)/8. Now you can solve fox AX.