Help with geometric relationship (1 Viewer)

BenHowe

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isnt just your cubing the function output each time. Like for some point a, you get f(a) for y=x^1/3 then cube it to get y=x, then cube it again to y=x^3
 

Ted_

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It could also be that they y=x is the mirror, and y=x^1/3 is the inverse of y=x^3. But idk about that. The questions seems a bit too vague.
 

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