Find the area bounded by the curve y = (4-x^2)^1/2, the x-axis and the y-axis in the first quadrant.
I know what the integral is, but whenever I try to solve it I end up with 16/3 - when the answer should be pi units^2
Any help would be appreciated. Thanks.
Last edited by Heresy; 20 Nov 2018 at 3:03 PM.
HSC 2019:
Business Studies l Legal Studies l Economics l MX1 l MX2 l Adv. English
ATAR GOAL: 99
Last edited by HeroWise; 20 Nov 2018 at 3:18 PM.
something that should be explicitly noted is that
(and in general, )
usually the bounds of the integral will mean that but one should still be careful when dealing with situations like this.
HSC 2018: English Adv. [80] • Maths Ext. 1 [98] • Maths Ext. 2 [95] • Chemistry [87] • Software Design [95]
ATAR: 97.40 | Uni Course: Advanced Mathematics (Hons) / Engineering (Hons) at UNSW
Yes definetly, i have been in situations where i got that wrong lol. aka Weird vector questions which has both multiple positive cases and the negative cases which i missed because of that silly thing
HSC 2019:
Business Studies l Legal Studies l Economics l MX1 l MX2 l Adv. English
ATAR GOAL: 99
It's called tex.
Here is a good guide to get started: A Short Guide to LaTeX
HSC 2018: English Adv. [80] • Maths Ext. 1 [98] • Maths Ext. 2 [95] • Chemistry [87] • Software Design [95]
ATAR: 97.40 | Uni Course: Advanced Mathematics (Hons) / Engineering (Hons) at UNSW
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