Series Question? (1 Viewer)

Alex499

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ok I know this is a little (ok way) late but I need help with this question on series. I'm doing Question 10 of 2001 and I get all the way to the end and get this line.

Bn = 1000(1.06)^n - 1200(1.06^n - 1)

Right and then the next line is
Therefore Bn = 1200 - 200(1.06)^n

What? where's the 200 come from?

oh god i'm so screwed
 

danz90

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Alex499 said:
ok I know this is a little (ok way) late but I need help with this question on series. I'm doing Question 10 of 2001 and I get all the way to the end and get this line.

Bn = 1000(1.06)^n - 1200(1.06^n - 1)

Right and then the next line is
Therefore Bn = 1200 - 200(1.06)^n

What? where's the 200 come from?

oh god i'm so screwed
I remember doing this question.
Initially, I couldn't get it.

But then I started it again, manipulated the equation around etc and finally got the answer. Just keep manipulating, playing around with the equation until u get to their result. I remember this took me a lot of lines of working.

No, ur not screwed dude ;) Remember, there are a large number of 2unit candidates that won't get more than like 2 or 3 marks in Q10.
 

UncoKane

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Omg I totally did this question today Alex!

And I got 6 for that whole section.

brb getting the piece of paper.
 

UncoKane

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$Bn = 1000(1.06)^n - 72(1.06^n - 1)/0.06
$Bn = 1000(1.06)^n - 1200(1.06^n - 1)

- 1200(1.06^n - 1) expands to - 1200(1.06)^n + 1200:

$Bn = 1000(1.06)^n - 1200(1.06)^n + 1200
$Bn = 1200 - 200(1.06)^n

I skipped a lot of steps because I cbf.

I don't think that helps haha sorry.
 
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Alex499

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haha thanks kane. I asked yahoo answers too and they gave me the answer hahaha
yay yahoo answers
And thanks Danz90 :) but it's not only question 10. It's like questions 1,2,3,4,5,6,7,8,9 and 10.
yeah screwed
 

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