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bmcdancer

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Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3
 

lyounamu

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bmcdancer said:
Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3
Answer:

n^10
_____________
8(n-6)
 

bored of sc

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bmcdancer said:
Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3
Since it's multiplication and division you can treat each bit like seperate fractions mulitplied together (this will become clearer below).

i.e. 23/26 * n7(n-6)-1/n-3

Hopefully it is clearer how you rearrange now.

1/23 (index law of am/an = am-n)* n7*n3/(n-6) (move negative power in denominator to numerator to make it positive, vice-versa for power in the numerator).

Now use am*an = am+n for n powers on numerator and multiply through each fraction, evaluating where necessary i.e. 23.

= n10/8(n-6)
 

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