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Thread: integrals and area

  1. #1
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    integrals and area

    need help with these pls

    integrate bewtween y=|x^2 -3x +2| and the x axis, between x=0 and x=3
    area between x^2=4y and y^2=4x (confused about if we should integrate y or x)
    area between y=-x^2+4x-3, y axis and the lines x=4 and y=4

  2. #2
    617 pages fan96's Avatar
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    Re: integrals and area

    1. The parabola is negative when . So when you take the absolute value, the only change in the graph is that that area will be flipped across the x axis to become positive. Same area, just the direction is changed. Therefore, to obtain the area between and the x-axis from to , we can integrate three parts of the curve separately (not to be confused with integration by parts...):

    Normally the middle integral would be negative, since the curve is under the x-axis at that point, but we can just take the absolute value.
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    2. It may be less confusing to integrate on the x-axis, but it doesn't matter which you pick, you just have to rearrange both equations in terms of the same variable.

    The parabola is just the parabola rotated 90 degrees clockwise about the origin.

    To obtain the area where they intersect, we can rearrange to make the subject, giving . Since these parabolas never intersect below the x-axis, we actually don't need the sign so we can remove it and take the positive root.

    Clearly, these integrals intersect at the origin and one other point, which is . Therefore (keeping in mind which curve is above the other) we can use the integral

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    3. If you draw a quick sketch it's easy to see that you are essentially being asked to find the area between and from to .

    The integral we need is just

    Last edited by fan96; 13 Feb 2018 at 8:29 PM.
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    HSC 2018 - [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design and Development]

    1(3√3) t2 dt cos(3π/9) = log(3√e) | Integral t2 dt, From 1 to the cube root of 3. Times the cosine, of three pi over nine, Equals log of the cube root of e.

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