Results 1 to 3 of 3

Thread: halp

  1. #1
    Cadet
    Join Date
    May 2016
    HSC
    2018
    Gender
    Female
    Location
    Dumpland, Nepal import
    Posts
    34
    Rep Power
    2

    halp

    (Cambridge Mathematics HSC 2U)
    5C
    (3) A particle is moving with acceleration function a = 8. Two seconds after time zero, it is stationary at the origin.
    (a) Integrate to find the velocity function.
    (b) Integrate again to find the displacement function.

    so like I got (a), velocity is 8t-16, but idk how to get the constant for (b)

    Answer is 4t^2-16t+16

  2. #2
    617 pages fan96's Avatar
    Join Date
    May 2017
    HSC
    2018
    Gender
    Male
    Location
    NSW
    Posts
    425
    Rep Power
    2

    Re: halp

    Quote Originally Posted by sodiumziha View Post
    Two seconds after time zero, it is stationary at the origin.
    This means that when .

    Your integral of velocity will be



    Knowing that the particle is at the origin after two seconds, you can work out the constant.
    HSC 2018: [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design]

    Goal: ≥92.00 for B Advanced Mathematics (Hons) / B Engineering (Hons) (Computer) at UNSW

  3. #3
    Junior Member HeroWise's Avatar
    Join Date
    Dec 2017
    HSC
    N/A
    Gender
    Male
    Location
    01001110 01100101 01110111 00100000 01010011 01101111 01110101 01110100 01101000 00100000 01010111 01100001 01101100 01100101 01110011
    Posts
    243
    Rep Power
    1

    Re: halp


Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •