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Thread: halp

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    halp

    (Cambridge Mathematics HSC 2U)
    5C
    (3) A particle is moving with acceleration function a = 8. Two seconds after time zero, it is stationary at the origin.
    (a) Integrate to find the velocity function.
    (b) Integrate again to find the displacement function.

    so like I got (a), velocity is 8t-16, but idk how to get the constant for (b)

    Answer is 4t^2-16t+16

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    617 pages fan96's Avatar
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    Re: halp

    Quote Originally Posted by sodiumziha View Post
    Two seconds after time zero, it is stationary at the origin.
    This means that when .

    Your integral of velocity will be



    Knowing that the particle is at the origin after two seconds, you can work out the constant.
    HSC 2018 - [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design and Development]

    1(3√3) t2 dt cos(3π/9) = log(3√e) | Integral t2 dt, From 1 to the cube root of 3. Times the cosine, of three pi over nine, Equals log of the cube root of e.

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    Re: halp


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