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16 Nov 2009, 5:53 PM ![]() | Calculus to physical world Q You can hide this advertisement by registering. Taken from a Trial:A missile is released from a plane flying horizontally at a height of 500 m and at a constant speed of 300m/s (i) Show that the equation of the horizontal component of the subsequent motion of the missile is given by x=300t, where t is time and x is horizontal displacement of missile (ii) A rocket launcher on the ground is immediately below the plane at the instant the missile is released. 2 secs later it is fired in an attempt to intercept the missile. It is fired in the same direction and in the same vertical plane as the missile. It is fired at an angle of 60 degrees to the horizontal at a speed of 100m/s. Determine how long after firing a possible interception occurs I need working and a good explanation of working in answers please. I have a really short solution which i don't understand at all. please help ty |
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| Prophet 9 | Re: Calculus to physical world Q Quote:
for the plane one, we know x2=300t but this is 2 seconds b4...so we can change it to be x2=300(t+2) if we want. x2=300t+600 assuming they do hit, we can just solve these 2 simultaneously. 100t=300t+600 t=-3 lol :P but i guess its true...the plane missile was dropped at 300m/s while the rocket launcher's projectile was shot at 100m/s and shot after....so they probably dont hit
__________________ High '09 UAI aim: 98.5 Year 12 subjects 09: Ext. 1+2 Maths Adv. Eng Biology Chemistry ~ Sydney Boys High School 2009 ![]() “Work smart. And when it is smart to work hard, work hard too” | |
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