3D Trig Question 2003 CSSA (1 Viewer)

bmn

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I understand most of it (as there are solutions with it), but theres one part of the solutions I don't understand.

h^2 . (tan20)^2 = h^2 . (tan10)^2 + 1600 . (tan20)^2 . (tan10)^2

this then goes to:

h^2 = [ 1600 (tan20)^2 . (tan10)^2 ] / [ (tan20)^2 - (tan10)^2 ]

How does this happen? Subbing the final solution back in works aswell.
 

jet

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They subtract the h2 term from the RHS to the LHS, factor out the h2 and then divide out the coefficient of h2 in the LHS to yield the fraction like so:
 

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