How do you draw these types of graphs (1 Viewer)

Dragonmaster262

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How do you draw graphs of e^f(x), loge f(x), and lnf(x) by just looking at the graph f(x). This is graph f(x):
 

hermand

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pretty sure this is mx2 not mx1, but yeah.

is there another side to this graph, ie the other part of the hyperbola in the opposite quadrant?
 

lychnobity

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Yeah, this is mx2 graphing.

but anyway: in general, apply the characteristics of the function (eg the 'e' characteristics) to the y values of f(x).
 

hermand

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anyways, the graph will be e^(3/x), so as x gets really small but greater than zero, the hyperbola will approach the y axis with an asymptote at x=0 [basically a steep hyperbola for the first quadrant], and [for x<0] therefore an open circle at x=0 and a line from this open circle that approaches y=1 from the bottom.

loge f(x) and ln f(x) are the same thing.

it will pass through the x-axis at x=3, and then basically be an upside down log fn.

you get these questions more when you don't get the actual equation, just the graph of it.
 
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kwabon

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anyways, the graph will be e^(3/x), so as x gets really small but greater than zero, the hyperbola will approach the y axis with an asymptote at x=0, and therefore an open circle at x=0 and a line from this open circle that approaches y=1 from the bottom.
one for one side right (x > 0), but wat if you were to consider the whole graph.
i know not in the question, but just hypothetically speaking, considering the whole graph of xy = 3, graph the e ^(f(x)).

interesting looking graph.
 

hermand

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one for one side right (x > 0), but wat if you were to consider the whole graph.
i know not in the question, but just hypothetically speaking, considering the whole graph of xy = 3, graph the e ^(f(x)).

interesting looking graph.
no, that bolded part is for x<0, i did consider the whole graph.
 

lychnobity

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It looks like this (see attachment)

Red is y = 3/x

Blue is e3/x
 

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