Restrictions on domain (1 Viewer)

[deswa1]

Hey guys,

For this question, obviously f(x) is undefined at x=-2 and when you work out the inverse function, it ends up being f(x)=2x/(1-x) which is undefined at x=1. So when you write the domain for part vi), is the domain all real x except x=1 or all real x except x=1,-2 as -2 isn't defined in the original domain? Or do we treat the inverse as an entirely new function so its just undefined for x=1?

 

[john-doe]

the domain of original doesnt affect the domain of the inverse as it translates to range of the new function...so if asked about the domain of inverse function, i think you consider it as new function...also if you put x=-2 in the new function, it will give you a definite answer implying that number is in the domain!

 

[deswa1]

the domain of original doesnt affect the domain of the inverse as it translates to range of the new function...so if asked about the domain of inverse function, i think you consider it as new function...also if you put x=-2 in the new function, it will give you a definite answer implying that number is in the domain!

Ok thanks

 

[asianese]

Cash in on 8 marks?? Or were there more parts haha

 

[mike12345678]

Cash in on 8 marks?? Or were there more parts haha

haha there are more parts. the questions he put up were part v and vi of the question so there had to be more