The amplitude of a particle moving in simple harmonic motion is 5 metres, and its acceleration when 2 metres from its mean position is 4 m/s^2. Find the speed of the particle at the mean position and when it is 4 m from the mean position.

do i form an equation of: x double dot = -n^2 (x - 2) ??

which becomes 4 = - n^2 (x-2) but then i dont know how to solve for n

or is the equation just 4 = -n^2 x 2

but then how do i get rid of the negative to get a value for n.

yeah i know really easy question, i just havent grasped the concept of shifting away from the centre. any reply will help heaps thanks!

## Bookmarks