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Thread: HSC 2017 MX1 Marathon

  1. #101
    I love trials pikachu975's Avatar
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by kawaiipotato View Post
    Where'd you get x^(4k-n)? The general term would have (2x^3)^(n-k) (1/x^k) which would be 3n - 4k wouldn't it
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  2. #102
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by pikachu975 View Post
    Where'd you get x^(4k-n)? The general term would have (2x^3)^(n-k) (1/x^k) which would be 3n - 4k wouldn't it
    He put the "k" with the x^3 part instead of with the 1/x part.

    (Remember, you can put it with either part.)

  3. #103
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    Re: HSC 2017 MX1 Marathon

    here's a pree cool nested root integral to try out;

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  4. #104
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by jathu123 View Post
    here's a pree cool nested root integral to try out;


  5. #105
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by jathu123 View Post
    here's a pree cool nested root integral to try out;

    Woahh you do nested root integrals in general maths cough
    Last edited by pikachu975; 5 Oct 2017 at 9:02 PM.
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  6. #106
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by pikachu975 View Post
    Where'd you get x^(4k-n)? The general term would have (2x^3)^(n-k) (1/x^k) which would be 3n - 4k wouldn't it
    Was the answer to this, multiples of 4?

  7. #107
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    Re: HSC 2017 MX1 Marathon

    Quote Originally Posted by shehan123 View Post
    Was the answer to this, multiples of 4?
    Yes
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    Re: HSC 2017 MX1 Marathon

    Last edited by 1729; 8 Oct 2017 at 5:09 PM.

  9. #109
    Taking a break! dan964's Avatar
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    Re: HSC 2017 MX1 Marathon

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