# Thread: Trig question

1. ## Trig question

I'm having trouble with this question. Normally i would use auxiliary method but I'm having difficulty. Thanks in advance.

(i) Express 2cosθ + 2cos(θ + π∕3) in the form Rcos (θ + α), where R > 0 and, 0 < α < π/2

(ii) Hence, or otherwise, solve 2cosθ + 2cos(θ + π∕3) = 3, for 0 < α < 2π  Reply With Quote

2. ## Re: Trig question

Hint: use the identity

And note that

is a constant.  Reply With Quote

3. ## Re: Trig question Originally Posted by mj8 I'm having trouble with this question. Normally i would use auxiliary method but I'm having difficulty. Thanks in advance.

(i) Express 2cosθ + 2cos(θ + π∕3) in the form Rcos (θ + α), where R > 0 and, 0 < α < π/2

(ii) Hence, or otherwise, solve 2cosθ + 2cos(θ + π∕3) = 3, for 0 < α < 2π
you have to expand the second term first using your sum of angles and simplify before you use your usual auxiliary angle.

fan96 did suggest a faster method, though that formula isn't in the syllabus anymore.  Reply With Quote

4. ## Re: Trig question

Thanks!  Reply With Quote