You need to use the concept
From there you integrate with respect to x then find the constant with the initial condition then multiply both sides by 2.
The acceleration a ms^-2 of a particle P moving in a straight line is given by a = 3(1-x^2) , where x metres is the displacement of the particle to the right of the origin. Initially the particle is at the origin moving with a velocity of 4ms^-1. Show that the velocity vms^-1 of the particle is given by v^2 = 16+6x-2x^3.
You need to use the concept
From there you integrate with respect to x then find the constant with the initial condition then multiply both sides by 2.
“Smart people learn from their mistakes. But the real sharp ones learn from the mistakes of others.”
― Brandon Mull
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