# Thread: Explanation for Calculus question needed

1. ## Explanation for Calculus question needed

The acceleration a ms^-2 of a particle P moving in a straight line is given by a = 3(1-x^2) , where x metres is the displacement of the particle to the right of the origin. Initially the particle is at the origin moving with a velocity of 4ms^-1. Show that the velocity vms^-1 of the particle is given by v^2 = 16+6x-2x^3.

2. ## Re: Explanation for Calculus question needed

You need to use the concept

$a = \frac{d}{dx} (\frac{1}{2}v^2)$

From there you integrate with respect to x then find the constant with the initial condition then multiply both sides by 2.

3. ## Re: Explanation for Calculus question needed

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