Basically yes we derive the equations for the motion of the ball once it has hit the advertising hoarding.

1. Set up the vector resolution (the right-angled triangle) for after the ball hits the sign with the information given in the question, i.e. V= 0.2(5√58). α = tan−1 (2/5).

2. Work out expressions for vertical velocity and vertical displacement (remember to include 52.5 as the constant as the ball hits the sign this high and thus is initially this high). Find the time when vertical displacement is 0, i.e. when the ball hits the ground.

3. Sub that value for T into the horizontal displacement which you have derived. Then subtract the distance you get from 75 as it is given that the sign is 75m away.

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