6.17, beginning of general solutions of trigonometric equations, please help! (1 Viewer)

crazyspacedust

New Member
Joined
Aug 2, 2018
Messages
2
Gender
Female
HSC
N/A
Question 1. part i) I'm extremely stuck :/ Any help would be much appreciated!

This is the question: 2sinxtanx-tanx+2sinx-1=0
 

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,249
Gender
Male
HSC
N/A
.: tanx(2sinx - 1) + 1(2sinx -1) = 0

.: (2sinx - 1)(tanx + 1) = 0

.: sin x = 0.5 or tan x = -1

You take it from there.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top