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Thread: Strange Induction

  1. #1
    Member HoldingOn's Avatar
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    Strange Induction

    http://prntscr.com/khe3aj

    Thanks. It looks easy but... maybe I am missing something.

  2. #2
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    Re: Strange Induction

    Have you tried expanding and rearranging?

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    Re: Strange Induction

    Quote Originally Posted by fan96 View Post
    Have you tried expanding and rearranging?
    Yes

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    Re: Strange Induction

    this expression = k3 + 3k2 + 3k ++ 1 + 5k + 5

    = (k3 + 5k) + 3k(k+1) + 6

    = 6M + 6 + 3k(k+1) (M an integer)

    But k(k+1) is always even, since if k is even, then it is; if k is odd, then k+1 is even. .: k(k+1) = 2N (N integer)

    .: the original expression becomes 6(M + 1 + N) = 6 x integer.
    Last edited by Drongoski; 12 Aug 2018 at 9:45 AM.
    pikachu975 and HoldingOn like this.
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