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Thread: Inverse

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    Member HoldingOn's Avatar
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    Inverse

    http://prntscr.com/kkcoio

    Could I get some help with part i, ii, iii, and iv. Thanks

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    Junior Member 1729's Avatar
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    Re: Inverse

    Quote Originally Posted by HoldingOn View Post
    http://prntscr.com/kkcoio

    Could I get some help with part i, ii, iii, and iv. Thanks

    http://prntscr.com/kkd19x

    idk if (iv) is right, and there also might be a faster way to do (ii)

    edit: it's meant to say f'(x) > 0 in (iii)

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    Re: Inverse

    Quote Originally Posted by 1729 View Post
    http://prntscr.com/kkd19x

    idk if (iv) is right, and there also might be a faster way to do (ii)

    edit: it's meant to say f'(x) > 0 in (iii)
    Thanks. How do you know by inspection the domain without solving an inequality?

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    Re: Inverse

    Quote Originally Posted by HoldingOn View Post
    Thanks. How do you know by inspection the domain without solving inequality?
    note the domain of inverse sine is -1 <= x <= 1

    if you graph the numerator and the denominator separately you will find that one is always greater than the other and hence the quotient is less than one for all real x.

    simplifying the LHS inequality gives you x^2 >= 0 which is also true for all real x.
    HoldingOn likes this.

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