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Thread: JRAHS 3U 2007 Trial Poly Question

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    JRAHS 3U 2007 Trial Poly Question

    Hey, I need help with this question. An explanation would be much appreciated as there are solutions (which I don't understand). The question is:

    P(x) is an odd polynomial of degree 3. It has (x+4) as a factor and, when it is divided by (x-3), the remainder is 21. Find P(x).

    The answer is:

    P(x) = 16x-x3

    Thanks

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    Re: JRAHS 3U 2007 Trial Poly Question

    Let .

    Because is odd, and therefore .

    .

    By the remainder theorem, and .

    Performing substitutions, we obtain

    APOLLO2609 likes this.
    HSC 2018: English Adv. [80] • Maths Ext. 1 [98] • Maths Ext. 2 [95] • Chemistry [87] • Software Design [95]

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