Mechanics Question (1 Viewer)

lolokay

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r is the radius of the hemisphere, not the radius from the centre of the circle the particle is travelling in - the radius of the circle will therefore be r sin@ (assuming you made the mistake I did)
so tan@ = v2/rsin@g
v2 = rg sin@tan@
 

shaon0

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lolokay said:
r is the radius of the hemisphere, not the radius from the centre of the circle the particle is travelling in - the radius of the circle will therefore be r sin@ (assuming you made the mistake I did)
so tan@ = v2/rsin@g
v2 = rg sin@tan@
lolokay why don't you do accelerated 4unit or something?
 

lolokay

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ii)
the total force *sin@ will be the acceleration (v2/rsin@) *mass
N = mv2/sin2@
but it is also the vector sum of the accelerating force and the gravitational force (mg)
N2 = m2v4/r2sin2 + m2g2
subbing in for N gives
N2 = mv2/r *N + m2g2
solving the quadratic, and taking the positive value, gives the required answer

shaon0 said:
lolokay why don't you do accelerated 4unit or something?
didn't have it at the school I was at
+ lol you have 666 posts
 

shaon0

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lolokay said:
ii)
the total force *sin@ will be the acceleration (v2/rsin@) *mass
N = mv2/sin2@
but it is also the vector sum of the accelerating force and the gravitational force (mg)
N2 = m2v4/r2sin2 + m2g2
subbing in for N gives
N2 = mv2/r *N + m2g2
solving the quadratic, and taking the positive value, gives the required answer


didn't have it at the school I was at
+ lol you have 666 posts
I realised that so i posted again...what school do you go to?
 

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