Using (d/dx) f(x)^1/2 = [2*f(x)^-1/2]/f'(x)Originally posted by Nelly

I have a Integration problem for all ya'll. Need description on how to do ASAP. Thank You:

INT: dx/[x(x^2+a^2)^1/2]

one on x times the square root of x squared plus a squared.

The Integral of: dx/[x(x^2+a^2)^1/2]

is (x^2 +a^2)^1/2

the square root of x squared plus a squared

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