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Complex factorising Help (1 Viewer)

Thread starter Jackson94
Start date Nov 22, 2011

Jackson94

Member

#1

Completely Factorise z^4 -4, thanks in advance

S

SIKKENT

Banned

#2

3(z-i+4)(z^2-6+2i)

A

AAEldar

Premium Member

#3

$z^4-4=(z^2-2)(z^2+2) \\\\ =(z-\sqrt{2})(z+\sqrt{2})(z-\sqrt{2}i)(z+\sqrt{2}i)$

nightweaver066

Well-Known Member

#4

$z^4 - 4$
$= (z^2 - 2)(z^2 + 2)$
$= (z + \sqrt{2})(z - \sqrt{2})(z^2 - 2i^2)$
$= (z + \sqrt{2})(z - \sqrt{2})(z + \sqrt{2}i)(z - \sqrt{2}i)$

S

SIKKENT

Banned

#5

nah sorry for being misleading, its (z^2+2)(Z^2-2)=(z+root2)(z-root2)(z+root2i)(z-root2i)

Jackson94

Member

#6

Thanks heaps guys!

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