HSC 2015 MX2 Integration Marathon (archive) (1 Viewer)

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Sy123

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Here post integrals for helping 2015 students with integration!

Do not post a question until the last one is answered

Do not post in the other thread because that is locked

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Sy123

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Re: MX2 2015 Integration Marathon

 

Sy123

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Re: MX2 2015 Integration Marathon

 

InteGrand

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Re: MX2 2015 Integration Marathon



One the one hand,




On the other hand, multiplying the numerator and denominator of the integrand of the original integral by cot4 x gives



Therefore,





 
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FrankXie

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Re: MX2 2015 Integration Marathon

lol a 100% magic done by substitution. anyone can find a way to play this magic:

 

Sy123

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Re: MX2 2015 Integration Marathon

lol a 100% magic done by substitution. anyone can find a way to play this magic:

Do you mean a substitution that does it all in one go?

The only thing I can think of at the moment is:







Where the dots are a tan inverse integral which is easy to compute

Is that what you were looking for?
 
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