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Thread: HSC 2017 MX2 Integration Marathon

  1. #226
    -insert title here- Paradoxica's Avatar
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    Re: HSC 2017 MX2 Integration Marathon

    If I am a conic section, then my e = ∞

    Just so we don't have this discussion in the future, my definition of the natural numbers includes 0.

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    Re: HSC 2017 MX2 Integration Marathon

    We should combine the two integration marathons don't you guys think?

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    Senior Member pikachu975's Avatar
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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by Drsoccerball View Post
    We should combine the two integration marathons don't you guys think?
    What's the other integration marathon?
    2016 HSC (Accelerated)
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  4. #229
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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by pikachu975 View Post
    What's the other integration marathon?
    "Extracurricular Integration Marathon." We might as well since questions are being posted here.

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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by Drsoccerball View Post
    "Extracurricular Integration Marathon." We might as well since questions are being posted here.
    No that would be a bad idea as the Extracurricular Integration Marathon deals with integrals at a level well beyond those expected at the MX2 level.

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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by Paradoxica View Post

  7. #232
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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by Paradoxica View Post

    By the reflection property we have

    A quick sketch () lets us deduce that:


    Hence
    Last edited by wu345; 17 Mar 2017 at 6:43 PM.

  8. #233
    -insert title here- Paradoxica's Avatar
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    HSC 2017 MX2 Integration Marathon

    Hence, or otherwise, evaluate:



    where n is a positive integer.
    If I am a conic section, then my e = ∞

    Just so we don't have this discussion in the future, my definition of the natural numbers includes 0.

  9. #234
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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by Paradoxica View Post
    Hence, or otherwise, evaluate:



    where n is a positive integer.

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    Re: HSC 2017 MX2 Integration Marathon

    Using a hyperbolic trigonometric substitution, show that:

  11. #236
    -insert title here- Paradoxica's Avatar
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    Re: HSC 2017 MX2 Integration Marathon

    Quote Originally Posted by wu345 View Post
    Your answer isn't even correct for n=2
    If I am a conic section, then my e = ∞

    Just so we don't have this discussion in the future, my definition of the natural numbers includes 0.

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