1. ## Complex number Q

Find the real numbers x and y such that:
(1+i)x + (2-3i)y = 10

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2. ## Re: Complex number Q

Originally Posted by nrumble42
Find the real numbers x and y such that:
(1+i)x + (2-3i)y = 10

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Equate real parts:

x + 2y = 10. (1)

Equate imaginary parts:

x – 3y = 0. (2)

Solving simultaneously yields x = 6 and y = 2.

3. ## Re: Complex number Q

Originally Posted by nrumble42
Find the real numbers x and y such that:
(1+i)x + (2-3i)y = 10

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Another slightly different method is to multiply the original equation by (1-i) then equation only the imaginary parts yields:
$-5y=-10$
and
equating the real part of the original part shows
$x = 4$

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