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Thread: James Ruse Trial Help

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    James Ruse Trial Help

    This question is from the 2006 4U JRAHS Trial. I got part a) but for part b), my answer is 71'34'. I am confused about their solution and think it may not be correct. Could someone clarify please?
    My solution gave that the truck starts at x=V^2sin(2theta)/3g, where y = the focus = -V^2cos(2theta)/2g. sub into eqn. I think it works when I graphed it here:

    (a) Ben’s Hot Wheel travels along an inclined ramp to jump over a truck. The Hot Wheel travels at an initial speed V m/s inclined at an angle θ to the horizontal at O, and acceleration due to gravity is g m/s2.
    The Wheel’s trajectory is given by y = x tanθ − gx2 sec2 θ . 2V 2
    (i) Write this equation in the general form of a parabola: (x – h)2 = 4a(y − k), 3
    where a, h, k are constants.
    (ii) Calculate the angle of projection, θ, if the range is three times the width of 3
    the truck and the top of the truck passes through the focus of equation in part (a).

    Attached as a screenshot, due to formatting issues.
    Screen Shot 2017-06-14 at 6.45.26 pm.png
    Screen Shot 2017-06-14 at 6.45.32 pm.png
    Last edited by mathpie; 15 Jun 2017 at 9:56 AM.

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