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Thread: Cambridge Complex Numbers Question

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    Cambridge Complex Numbers Question

    Just picked up 4 unit and we have started with complex numbers, so far its fairly easy but still trying to understand the new/abstract concepts.

    Any help with the following question is greatly appreciated

    z has modulus r and argument (theta). Find in terms of r and (theta) the modulus and one argument of:

    c) iz

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    Re: Cambridge Complex Numbers Question

    modulus is given by sqrt(a^2 + b^2) where those values come from a + ib.

    So in the above b=z, a=0

    So modulus is z

    For the argument(theta) draw out the complex number on an axis of a and b(this one being imaginary)

    Find the angle formed through trig rules

    In this case it’s just Pi/2
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    Re: Cambridge Complex Numbers Question

    Cheers for the response So just letting z1 = 0 + iz, you consider z to be the imaginary part of the expression and not as i(a+ib)? If yes then it makes sense that as there is no real part of z1 the angle must be pi/2 is this correct?
    Last edited by jjjcjjj892; 29 Oct 2017 at 1:58 PM.

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    Re: Cambridge Complex Numbers Question



    if you havent learnt the above stuff, then let z = a+ib, so iz = i(a+ib) = -b+ia. Now using the modulus formula, |iz| = sqrt( (-b)^2 +(a)^2 ) = r
    Note that multiplying a complex number by i means thats you are rotating it by pi/2 radians anticlockwise, hence the new argument will be the argument of z + pi/2, which is theta + pi/2

    Edit: z1 = a+ib, where 'a' and 'b' are purely real numbers, so when z1=0+iz, b cannot be z (as z is obviously a non real number). So you need to expand it instead.
    Last edited by jathu123; 29 Oct 2017 at 2:10 PM.
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    Re: Cambridge Complex Numbers Question

    yep, jathu's spot on.
    Jazz...not so much

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    Re: Cambridge Complex Numbers Question

    Quote Originally Posted by jjjcjjj892 View Post
    Just picked up 4 unit and we have started with complex numbers, so far its fairly easy but still trying to understand the new/abstract concepts.

    Any help with the following question is greatly appreciated

    z has modulus r and argument (theta). Find in terms of r and (theta) the modulus and one argument of:

    c) iz
    Multiplying by i is just a geometric anticlockwise rotation of pi/2, there is no enlargement or dilation so iz will also have modulus r.

    As above, an argument would be pi/2 + theta

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    Re: Cambridge Complex Numbers Question

    Ah makes sense, cheers for the response, I had thought of splitting the mod of iz up like that but was confused with what to do with mod(i), only now do I realise its 1, seems so simple now ahah thanks for making me see that

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    Re: Cambridge Complex Numbers Question

    Well i = 0+1i, so draw it out on the Argand plane and you'll see the mod has to be 1

    Yes it's abstract but you can still draw a picture
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