1. ## complex numbers q

so theres this q,
am^2+am+c=0 where m is complex number and a,b,c are real
so we need to use conjugate theorems to show that a(m conjugate)^2 +b(m conjugate) +c=0

i thought we cn just say that conjugate of m is a root, but how do we use conjugate theorems :/

2. ## Re: complex numbers q

Originally Posted by sssona09
so theres this q,
am^2+am+c=0 where m is complex number and a,b,c are real
so we need to use conjugate theorems to show that a(m conjugate)^2 +b(m conjugate) +c=0

i thought we cn just say that conjugate of m is a root, but how do we use conjugate theorems :/
$\noindent Take the conjugate of both sides and use \overline{z_1+z_2+\ldots +z_n}=\overline{z_1} + \overline{z_2} + \ldots + \overline{z_n} and \overline{z_1 \times z_2 \times \ldots \times z_n} = \overline{z_1} \times \overline{z_2} \times \ldots \times \overline{z_n} and the fact that the complex conjugate of a real number is itself.$

3. ## Re: complex numbers q

Originally Posted by 1729
$\noindent Take the conjugate of both sides and use \overline{z_1+z_2+\ldots +z_n}=\overline{z_1} + \overline{z_2} + \ldots + \overline{z_n} and \overline{z_1 \times z_2 \times \ldots \times z_n} = \overline{z_1} \times \overline{z_2} \times \ldots \times \overline{z_n} and the fact that the complex conjugate of a real number is itself.$
thank you <3

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