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Thread: HSC 1991 I think! Can anyone help?

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    HSC 1991 I think! Can anyone help?


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    Junior Member HeroWise's Avatar
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    Re: HSC 1991 I think! Can anyone help?

    May i know where u got this question from?

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    Re: HSC 1991 I think! Can anyone help?

    i)

    Since ,



    You can use long division and then divide by (since ) to obtain the desired result. It's rather unintuitive, though.
    __________________________________________________ __________________________________________________ ____________________

    ii) Consider the expansions of

    .
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    iii) There are six solutions to the equation in part i). By performing the substitution in ii), you've reduced it down to three, by making three of those solutions the same as the other three.

    Find these three unique solutions and use the product of roots and the properties of in the first and second quadrants to obtain the answer.

    HSC 2018 - [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design and Development]

    1(3√3) t2 dt cos(3π/9) = log(3√e) | Integral t2 dt, From 1 to the cube root of 3. Times the cosine, of three pi over nine, Equals log of the cube root of e.

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    Re: HSC 1991 I think! Can anyone help?

    Quote Originally Posted by HeroWise View Post
    May i know where u got this question from?
    HSC 1992 Q7

    If you are interested in these type of questions, I'd recommend checking out coroneos (The supplementary book), it has a lot of similar/Interesting questions.

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    Taking a break! dan964's Avatar
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    Re: HSC 1991 I think! Can anyone help?


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