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AGB

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"In complex analysis, an entire function is defined as a function which is infinitely differentiable at every point in C (for example: constants, polynomials, e^x, etc.). Picard's Theorem says that every nonconstant entire function f misses at most one point (i.e. f(C) = C or C-{x0}). For example, every nonconstant polynomial hits every point, and e^x misses only 0.

Now consider the function f(x) = e^(e^x). Since e^x is entire, f is also entire by the chain rule. But it misses 0 since the base e^y misses 0, and it misses 1 since the top e^x misses 0 so that e^(e^x) misses e^0 = 1. But by Picard's Theorem there can be only one missing point, so the two missing points must be the same. Therefore, 0 = 1."

i got this in an email.....
 

McLake

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Just one question, what is Picard's Theorm? I know you got this in an email, so you probably won't know, but it seems the entire argument relys on this theorm, and I have never heard of it ...
 

bobo123

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rofl
at first i thought it was some star trek bs keke :p
 

flyin'

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arh ... all these letters (put them away! :p) ... and only 1s and 0s ... :p

btw none of it makes much sense cos my mind is still on hols!
 
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ND

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Originally posted by AGB
which is infinitely differentiable at every point in C
That part i don't understand. What does "infinately differentiable" mean? And is C the complex number field?
 

McLake

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Originally posted by ND


That part i don't understand. What does "infinately differentiable" mean? And is C the complex number field?
I "think" infinately differentiable means that when you differentiate, you have a expression that is differentiable (but not 0). So an x^5 polynomial is NOT infinatly differentiable, as it will become a constant, but e^x is.

I guess C stands for complex no feild ...
 
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ND

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Originally posted by McLake


I "think" infinately differentiable means that when you differentiate, you have a expression that is differentiable (but not 0). So an x^5 polynomial is NOT infinatly differentiable, as it will become a constant, but e^x is.

I guess C stands for complex no feild ...
Thats what i thought, but following on it says "(for example: constants, polynomials, e^x, etc.) ", and constants and polynomials don't fit that description.
 

Lazarus

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You can differentiate 0... you get 0. :)

The graph of y = e^(e^x) looks like y = e^x shifted up one unit and made slightly steeper so that it cuts the y-axis at e.

Not only does it miss 0 and 1, but it misses every point below the x-axis as well (which is the same for y = e^x).
 

McLake

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Originally posted by Lazarus
You can differentiate 0... you get 0. :)
I know, but then all equations would be infinatley differentiable ...
 

McLake

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Originally posted by bookboy18
Whoa Whoa Whoa

How do you differenciate?
You don't know of "d/dx"? What level of maths do you do ...
 

McLake

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Originally posted by bookboy18
General.

Thats why this thread is freaky
Why is a student who does general in the ext2 forum?

---------------------------------------------

Some more freaky stuff:

sqrt(-1) = i <-- complex number
e^(i * pi) = 1
 

Lazarus

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Originally posted by McLake
I know, but then all equations would be infinatley differentiable ...
It's not specifically referring to equations, it's referring to functions... and functions that have discontinuities or cusps, for example, are not differentiable at those points.

From what I can gather, an 'entire' function is one that has a complex derivative at every point in its domain. Been too long since I've done anything with complex numbers. :)
 

McLake

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Originally posted by bookboy18
I was curious to see what people would say in this forum, McLake
And now we've scared you off ...
 

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