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DaGr81

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can someone explain to me
fitzpatrick exercise 32(D)
question 30 part a ....it doesnt make sense when u find the gradient of OM unless im making some stupid stupid mistake
 

Harimau

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a) Find M first. M [(p+q)/2 , (1/p+1/q)/2)

Skipped some steps, used gradient formula to find gradient of PQ.
Gradient of PQ= -1/(pq)

Skipped some steps, used gradient formula to find gradient of OM.
Gradient of OM= 1/pq

Given: Gradient of OM x Gradient of PQ = -1

(Therefore) -1/(pq)^2 = -1
(Therefore) q = 1/p

b) Using the formula for tangent of a hyyperbola, (x.x1/a^2 - y.y1/b^2=1)

eqn of tgt at P: px/a^2- y/pb^2 =1
eqn of tgt at Q: x/pa^2 - yp/b^2 =1 (q=1/p, from above)


(To be Continued, let me finish it on paper)
 

spice girl

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posting the actual question would be good, seeing as I (an ex-student) have returned my fitz to the school
 

DaGr81

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thanks yeah i got both answers but
in the back they have
+/- 1/p and i dunno where they got that from
 

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