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Thread: Help!

  1. #1
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    Exclamation Help!

    can somebody please help how to find acceleration in terms of velocity. it's probably easy but i can't find it anywhere!

  2. #2
    chocoholic mannnnndy's Avatar
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    do u mean like the special result where a = d/dx(1/2v^2)?
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  3. #3
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    i know how to integrate an acceleration equation using that and vdv/dx.

    but how do you find acceleration in terms of velocity by differentiating?

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    you get acceleration by differentiating v, if v is a function of t
    a=dv/dt

    if v is a function of x
    a=dv/dx(1/2 v^2)

    i hope i got the whole function thing right, because i always mix them up. when i say v is a function of x i mean v=2x+4 or whatever (just in case i didn't get the terminology right)

    hope that helps but..

  5. #5
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    hmmm alright but how do you get a = 2v + 4 by differentiating? i can see how you get a = 2t + 4 and a = 2x + 4 but what about
    a = 2v + 4?

  6. #6
    chocoholic mannnnndy's Avatar
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    ive never actually seen an equation where a = 2v + 4 or whatever. i had a look at the 3u & 4u syllabus and did not see it anywhere. r u sure it even exists?
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  7. #7
    Retired Lazarus's Avatar
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    If you found v as a function of x, and then found a as a function of x, you might be able to rearrange the former and substitute for x into the latter.

    Could possibly do it with time instead of displacement as well.
    Lazarus
    Et in arcadia ego...

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